New Delhi, March 3: National carrier Air India on Tuesday issued a statement confirming that one of its passengers who flew on AI-154 Vienna-Delhi flight on February 25, tested positive of COVID-19. Taking to Twitter, the airline has urged all the passengers of the AI-154 flight to follow the health advisory that has been put up by the Union Ministry of Health. "This is for the attention of passengers who flew on AI-154 Vienna-Delhi of 25th February 2020. One of the passengers has tested positive for coronavirus. Please follow the protocol notified by the Ministry of Health regarding Coronavirus. Kindly visit  mohfw.gov.in/diseasealerts/novel-corona-virus", the tweet read. Coronavirus Scare in India: PM Narendra Modi Says Extensive Review Done, 'No Need to Panic'.

The Ministry of Health has put in place a travel advisory for Indians, discharge policy for suspect or confirmed novel Coronavirus (2019-nCoV) cases, guidelines on Clinical management of severe acute respiratory illness,  Guidance on Surveillance for human infection with 2019-nCoV and other details related to Coronavirus.

Here's the tweet:

After a Delhi resident, who traveled in the Air India flight from Vienna to Delhi flight on February 25, tested positive for coronavirus, the national carrier asked the flight crew of that day to be on a self-imposed home quarantine for 14 days to prevent the outbreak of coronavirus in India. 10 crew members including the Commander and the Co-pilot of the flight have been told to be on a 14 day quarantine at their homes, a senior Air India official said.

On Monday, two new positive cases of coronavirus were reported- one from Delhi and the other one from Telangana. The Union Health Ministry said  the Delhi man had travelled to Italy while the patient from Telangana had visited Dubai.

(The above story first appeared on LatestLY on Mar 03, 2020 04:58 PM IST. For more news and updates on politics, world, sports, entertainment and lifestyle, log on to our website latestly.com).