The Odisha Public Service Commission, OPSC has invited applications for the posts of Junior Assistant(Group C). Those who are interested can check the eligibility criteria, and selection process through the official website of OPSC opsc.gov.in. Through this recruitment drive, a total of 15 vacant posts will be filled in the organization. The online application form will begin from Friday, April 22. It is to be noted that the last date to submit the application is May 23, 2022.

OPSC Recruitment 2022: Vacancy Details

  • Name of the Post: Junior Assistant(Group C)

Number of vacancies available for each category

  • Unreserved: 06 posts

  • SEBC: 01 posts

  • SC: 03 posts

  • ST: 05 posts

OPSC Recruitment 2022: Eligibility Criteria

A candidate must hold a Bachelor's Degree in any discipline from any University incorporated by an Act of Parliament or State Legislature in India or Education Institution established by an act of Parliament deemed to be a University under Section 3 of the University Grants Commission, Act 1956 or a Foreign University approved by the Central Skill. DSSSB Recruitment 2022: Notification Released For 168 Posts At dsssb.delhi.gov.in; Check Details Here

Candidates who want to apply for the posts mentioned above can check the education qualification, age limit, and selection process through the official notification given below. AIIMS Bhubaneswar Recruitment 2022: Vacancies Notified for 9 Posts at aiimsbhubaneswar.nic.in; Check Details Here

OPSC recruitment 2022 age limit: The candidates should be between the age of 21 to 38 years as on January 1, 2022.

OPSC Recruitment 2022: How to Apply Online?

Interested and eligible candidates can apply for the posts through the official website of OPSC at opsc.gov.in.

OPSC Recruitment 2022: Selection Procedure

Candidates will be selected on the basis of the Written Exam and Skill tests.

(The above story first appeared on LatestLY on Apr 21, 2022 02:53 PM IST. For more news and updates on politics, world, sports, entertainment and lifestyle, log on to our website latestly.com).